Q:
Help with simple trigonometry problem.
Can someone explain how the following formula works? I'd like to use it. Thanks!
\begin{eqnarray}
\lnot 2\cos b - \sin b &=& \pm 4\cos c - 3\cos b \\
\lnot (-2\sin b + \cos b) &=& \pm 4\cos c -3\sin b
\end{ 50e0806aeb haneld
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